The pH of `0.04M` of `BCl` solution at `25^(@)C` is (Given, `pK_(b)` of `BOH=6` )

The pH of 0.25 M Ba(OH)_2 solution is:

What is the pOH of 0.1 M KB (salt of weak acid and strong base) at 25^(@)C ? (Given : pK_(b) of B^(-) =7)

The potential of the cell at 25^(@)C is Given pK_(a) of CH_(3)COOH and pK_(b) of NH_(4)OH=4.74

The potential the cell at 25^(@)C is Given pK_(b) of NH_(4)OH=4.74 (a) 0.05V (b) -0.05V (c) -0.28V (d) 0.28V

pH of 0.01 M aq. solution of HA is 4. Find the value of pK_(a) of HA at 25^(@)C.

The pH of 0.2 M aqueous solution of NH_4Cl will be (pK_b of NH_4OH = 4.74, log 2 = 0.3)

The pH of 1 M PO_(4)^(3-) (aq) solution (given pK_(b) of PO_(4)^(3-) = 2 ) is

What is the pH of a 0.50M aqueous NaCN solution ? (pK_(b)of CN^(-)=4.70)

Calculate pH of 10^(-7)M of NaOH solution at 25^(@)C (take log0.618=0.21)

At 25^(@) C dissociation constants of acid HA and base BOH in aqueous solution are same. The pH of 0.01 M solution of HA is 5. The pOH of 10^(-4) M solution of BOH at the same temperature is :