An element with density `3gcm^(-3)` forms a bcc lattice with edge length of `3times10^(-8)cm`. The molar mass of the element is : `(N_(A)=6times10^(23)mol^(-1))` (a) `48*6gmol^(-1)` (b) `24.3gmol^(-1)` (c) `60gmol^(-1)` (d) `56gmol^(-1)`

An element with density 11.2"g cm"^(-3) forms a fcc lattice with edge length of 4xx10^(-8) cm. Calculate the atomic mass of the element.

An element with density 2.8 cm^(3) forms a f.c.c unit cell with edge length 4xx10^(-8) cm. calculate the molar mass of the element. Given: (N_(A)=6.022xx10^(23)) mol^(-1)

An element with density 11.2 g cm^(-3) forms a f. c. c. lattice with edge length of 4xx10^(-8) cm. Calculate the atomic mass of the element. (Given : N_(A)= 6.022xx10^(23) mol^(-1)

An element with density 10 g cm^(-3) forms a cubic unit cell with edge length 3xx10^(-8)cm . What is the nature of the cubic unit cell if the atomic mass of the element is 81 g mol^(-1) .

A body centred cubic element of density, 10.3 g cm^(-3) has a cell edge of 314 pm. Calculate the atomic mass of the element. ( N_A = 6.023 xx 10^(23) mol^(-1) )

An element 'X' crystallises as face centred cubic lattice with edge length of 460 pm. The density of the element X, when molar mass of X atom is 60 g mol^(-1) is

Molar mass of electron is nearly : (N_(A) = 6 xx 10^(23)) , mass of e^(-) = 9.1 xx 10^(-31)Kg

(i) (a) Following is the schematic alignment of magnetic moments : What type of magnetism is shown by this substance ? (b) What type of stoichiometric defect is shown by (i) KCI (ii) AgCl ? (ii) An element with density 11.2 g cm^(-3) forms a fcc lattice with length of 4xxd10^(-8) cm. Calculate the atomic mass of the element. (N_(A)=6.02xx10^(23) mol^(-1)) .

3.011 xx 10^22 atoms of an element weighs 1.15 gm . The atomic mass of the element is :