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C(s)+O(2)(g)⇔CO(2)(g) Mole of O(2) and C...

`C(s)+O_(2)(g)⇔CO_(2)(g)` Mole of `O_(2)` and `CO_(2)` are `5` mole and `10` mole at equilibrium respectively.If `K_(p)` and `K_(c)` of the above reaction are `x&y`, then find the value of `(x-y)`.

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