`dy/dx+2y=4x`

The integrating factor of (dy/dx)+2y = xe^(4x) is

Solve the following differential equations: (dy)/(dx)+2y=xe^(4x)

Find dy/dx , y=(x^2+4)/(x+2)

(dy)/(dx)-2y=x

Solve (y-3x+3)dy/dx=2y-x-4

find dy/dx if y = (x^(2) - 4x+5) (x^(3) - 2)

Write integrating factor differential equations x^2 (dy)/(dx)+y= x^4

The slope of its tangent at (x,y) is dy/dx = ((x-2)^2+(y+4))/(x-2) and the curve passes through origin then the point which passes through the curve is

Solve log(dy)/(dx)=4x-2y-2, given that y=1 when x=1

Solve the following differential equations. 2(x-3y+1)(dy)/(dx)=(4x-2y+1)