`sin^2 theta + cos^2 theta=?`.

prove that sin^2theta+cos^2theta=1

Complete the following activity by filling the boxes sin^(2) theta+cos^(2) theta=square ……….(Identity) Dividing each term by cos^(2)theta (sin^(2)theta)/(cos^(2)theta)+(cos^(2)theta)/(cos^(2)theta)=(square)/(cos^(2)theta) :.square+1=square

(sin2 theta)/(1+cos2 theta)=

Evaluate sin^2theta/cos^2theta+1

(sin2 theta)/(1-cos2 theta)

If 5sin^2 theta+cos^2theta=2 then sin theta=

If |[1+sin^2theta, cos^2 theta,4sin 2theta] , [sin^2theta, 1+cos^2theta,4sin2theta] , [sin^2theta,cos^2theta,4sin2theta-1]|=0 and 0 lt theta lt pi/2 then cos4theta=

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

If A=[cos2 theta sin2 theta-sin2 theta cos2 theta], find A^(2)