`[L^(1)M^(1)T^(-2)]` is the dimensional formula for a)velocity b) acceleration c) force d) work

[ML^(-1)T^(-2)] is the dimensional formula of

[ML^(2)T^(-3)A^(-1)] is the dimensional formula for

The dimensional formula ML^2T^(-2) represents

The dimensional formula ML^(2)T^(-2) stands for

The dimensional formula [ML^(-1)T^(-2)] is for the quantity

Find the dimensional formula of the following question : (a) Density (b) Velocity (c) Acceleration (d) Momentum (e) Force (f) Work of energy (g) Power (h) Pressure

Force xx velocity =x . The dimensional formula of x is

The mechanical equivalent of heat (1) has the same dimensional formula as heat (2) has the same dimensional formula as worked (3) has the same dimensional formula as energy (4) is dimensionless

Suppose the dimensional formula for acceleration, velocity length are alpha beta^(-2), alphabeta^(-1) and alpha gamma . Then the dimensional formula for the coefficient of friction is

The expression S = a/b (1 - e^(-bt)) is dimensionally true. The dimensional formula of a and b are respectively, (if S is the displacement at any instant t,)