Find `theta` :

x = a `Cos( theta/2 ) `
y = b `Sin( theta/2 )`

If x = a cos theta and y = b sin theta , find (dy)/(dx)

x=a cos theta,y=b sin theta then find dy/dx

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

(x) / (a) cos theta + (y) / (b) sin theta = 1, (x) / (a) sin theta- (y) / (b) cos theta = 1 then (x ^ (2)) / (a ^ (2)) + (y ^ (2)) / (b ^ (2)) =

x=a(theta-sin theta), y= a (1+cos theta) find (dy)/dx "at " " " theta=pi/2 .

The eliminant of theta from x cos theta - y sin theta = 2 , x sin theta + y cos theta = 4 will give