`(dy/dx)+(y/x)`=`y^2`

The solution of (dy)/(dx)+(y)/(x)logy=(y)/(x^(2))(logy)^(2), is

If (dy)/dx = (xy)/(x^2 + y^2), y(1) = 1 and y(x) = e then x =

Find the particular solution of the differential equation (dy)/(dx)=(x y)/(x^2+y^2) given that y=1\ w h e n\ x=0.

x+y(dy/dx)=2y

Solve the following differential equation: xy(dy)/(dx)-y^2=(x+y)^2e^(-y//x)

Solve the following initial value problem: x y(dy)/(dx)=(x+2)(y+2),\ y(1)=-1

9. (dy)/(dx)=(y^(2)-y-2)/(x^(2)+2x-3)

Solve (dy)/(dx)=((x+y)^2)/((x+2)(y-2))

x(dy)/(dx)+y=y^(2)x^(3)cos x

If x ylog(x+y)=1 , prove that (dy)/(dx)=-(y(x^2y+x+y))/(x(x y^2+x+y))