Sanjay and Manoj lent Rs. 30000 each at 6% per annum for a period of 6 years and 10 years respectively. Find the difference in interest paid by them.

Options

A. Rs. 1080
B. Rs. 3600
C. Rs. 7200
D. Rs. 1800

Answer

To find the difference in interest paid by Sanjay and Manoj, we will calculate the simple interest for both of them and then find the difference.

### Step-by-Step Solution:

1. **Identify the given values:**
- Principal (P) = Rs. 30,000
- Rate of interest (R) = 6% per annum
- Time for Sanjay (T1) = 6 years
- Time for Manoj (T2) = 10 years

2. **Calculate the simple interest for Sanjay (SI1):**
The formula for simple interest is:
\[ \text{SI} = \frac{P \times R \times T}{100} \]
For Sanjay:
\[ \text{SI1} = \frac{30000 \times 6 \times 6}{100} \]
\[ \text{SI1} = \frac{1080000}{100} = 10800 \]

3. **Calculate the simple interest for Manoj (SI2):**
For Manoj:
\[ \text{SI2} = \frac{30000 \times 6 \times 10}{100} \]
\[ \text{SI2} = \frac{1800000}{100} = 18000 \]

4. **Find the difference in interest paid by them:**
\[ \text{Difference} = \text{SI2} - \text{SI1} \]
\[ \text{Difference} = 18000 - 10800 = 7200 \]

### Final Answer:
The difference in interest paid by Sanjay and Manoj is Rs. 7,200.

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