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Manpreet took part in an interschool rac...

Manpreet took part in an interschool race competition He cylcled 2.7 km, ran for `(2)/(3)` hour and walked the remaining 500 m of the race. If the total distance of the race was 12 km, then find his running speed

A

13.2 km/hr

B

12 km/hr

C

7.5 km/hr

D

8.8 km/hr

Text Solution

AI Generated Solution

The correct Answer is:
To find Manpreet's running speed, we can follow these steps: ### Step 1: Determine the total distance of the race The total distance of the race is given as 12 km. ### Step 2: Calculate the distance cycled and walked Manpreet cycled 2.7 km and walked 500 m. First, we need to convert the distance walked into kilometers: - 500 m = 500/1000 km = 0.5 km ### Step 3: Calculate the total distance cycled and walked Now, we add the distance cycled and the distance walked: - Distance cycled = 2.7 km - Distance walked = 0.5 km - Total distance cycled and walked = 2.7 km + 0.5 km = 3.2 km ### Step 4: Calculate the distance run To find the distance run, we subtract the total distance cycled and walked from the total distance of the race: - Distance run = Total distance - Distance cycled and walked - Distance run = 12 km - 3.2 km = 8.8 km ### Step 5: Determine the time spent running The time spent running is given as \( \frac{2}{3} \) hour. ### Step 6: Calculate the running speed Speed is calculated using the formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] Substituting the values we have: \[ \text{Speed} = \frac{8.8 \text{ km}}{\frac{2}{3} \text{ hour}} \] To divide by a fraction, we multiply by its reciprocal: \[ \text{Speed} = 8.8 \text{ km} \times \frac{3}{2} \] Calculating this gives: \[ \text{Speed} = \frac{8.8 \times 3}{2} = \frac{26.4}{2} = 13.2 \text{ km/h} \] ### Final Answer Manpreet's running speed is **13.2 km/h**. ---
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