a. We have `3/(x+8)=4/(6-x)` `implies18-3x=4x+32implies7x=14impliesx=-2` b. We have `(2^(x-1).4^(2x+1))/(8^(x-1))=64` `implies(2^(x).2^(-1).4^(2x).4)/(8^(x).8^(-1))=64=1/(4^(x)).4^(2x).16=64implies4^(x)=64/16=4` On comparing we get x=1 c. We have `4^(x)-4^(x-1)=24` `implies4^(x)-(4^(x))/4=24implies4^(x)(1-1/4)=24implies(2^(2))^(x)=(24xx4)/3=32` `implies2^(2x)=2^(5)` On comparing we get `2x=5impliesx=5/2` Now `(2x)^(x)=(5)^(5//2)` d. We have `4^(x+1)=256` `implies4^(x+1)=(4)^(4)` On comparing we get `x+1=4impliesx=3`
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