The perpendicular distance of the point `(-7,8)` from the x-axis is _______ units.

Options

A. 7
B. 8
C. `-7`
D. 1

Answer

To find the perpendicular distance of the point \((-7, 8)\) from the x-axis, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Coordinates**: The given point is \((-7, 8)\). In this coordinate, \(-7\) is the x-coordinate and \(8\) is the y-coordinate.

2. **Understand the Concept of Perpendicular Distance from the X-Axis**: The perpendicular distance from any point to the x-axis is simply the absolute value of the y-coordinate of that point. This is because the x-axis is defined as \(y = 0\).

3. **Calculate the Perpendicular Distance**:
- The y-coordinate of the point is \(8\).
- Therefore, the perpendicular distance from the point \((-7, 8)\) to the x-axis is \(|8| = 8\) units.

4. **Conclusion**: The perpendicular distance of the point \((-7, 8)\) from the x-axis is \(8\) units.

### Final Answer:
The perpendicular distance of the point \((-7, 8)\) from the x-axis is **8 units**.

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