If `(-3,2)` is a solution of the linear equation `5x+3ky=3`, then the value of k is _______

Options

A. 3
B. 6
C. 5
D. 2

Answer

To find the value of \( k \) in the linear equation \( 5x + 3ky = 3 \) given that the point \((-3, 2)\) is a solution, we can follow these steps:

### Step 1: Substitute the values of \( x \) and \( y \)
We know that \((-3, 2)\) is a solution of the equation, which means we can substitute \( x = -3 \) and \( y = 2 \) into the equation:

\[ 5(-3) + 3k(2) = 3 \]

### Step 2: Simplify the equation
Now, we simplify the left-hand side:

\[ -15 + 6k = 3 \]

### Step 3: Isolate the term with \( k \)
Next, we need to isolate the term with \( k \). We can do this by adding \( 15 \) to both sides of the equation:

\[ 6k = 3 + 15 \]

### Step 4: Combine the constants
Now, we combine the constants on the right side:

\[ 6k = 18 \]

### Step 5: Solve for \( k \)
Finally, we divide both sides by \( 6 \) to find the value of \( k \):

\[ k = \frac{18}{6} = 3 \]

Thus, the value of \( k \) is \( 3 \).

### Summary
The value of \( k \) is \( 3 \).

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