Kirti walks 30 metres towards North. She then turns left and walks 50 metres. She again turns left and walks 30 metres. Further, she moves 10 metres after turning to the right. How far is she from her original position ?

Options

A. 45 metres
B. 50 metres
C. 60 metres
D. 40 metres

Answer

To solve the problem step by step, we will track Kirti's movements and calculate her final distance from the original position.

### Step-by-Step Solution:

1. **Starting Point (S)**: Kirti starts at point S (0,0).

2. **First Movement**: Kirti walks 30 meters towards North.
- New position after this movement:
- Coordinates: (0, 30)

3. **Second Movement**: She then turns left (towards West) and walks 50 meters.
- New position after this movement:
- Coordinates: (-50, 30)

4. **Third Movement**: She again turns left (towards South) and walks 30 meters.
- New position after this movement:
- Coordinates: (-50, 0)

5. **Fourth Movement**: She moves 10 meters after turning to the right (which is towards West).
- New position after this movement:
- Coordinates: (-60, 0)

6. **Calculating Distance from Original Position**:
- The original position (S) is at (0,0) and her final position (P) is at (-60, 0).
- The distance can be calculated using the formula for distance between two points:
\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
- Here, \( (x_1, y_1) = (0, 0) \) and \( (x_2, y_2) = (-60, 0) \):
\[ \text{Distance} = \sqrt{(-60 - 0)^2 + (0 - 0)^2} = \sqrt{(-60)^2} = 60 \text{ meters} \]

### Final Answer:
Kirti is 60 meters away from her original position.

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