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Place value of a digit decreases by time...

Place value of a digit decreases by times as it moves place by place from left to right.

A

`100`

B

`(1)/(10)`

C

`10`

D

`1000`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding how the place value of a digit decreases as it moves from left to right, we can break it down step by step. ### Step-by-Step Solution: 1. **Understanding Place Value**: - Each digit in a number has a specific place value depending on its position. For example, in the number 654321, the place values from left to right are: - 6 (hundred-thousands) - 5 (ten-thousands) - 4 (thousands) - 3 (hundreds) - 2 (tens) - 1 (units) 2. **Identifying the Movement**: - When we talk about moving from left to right, we are moving from a higher place value to a lower place value. For instance, if we take the digit 4 in the number 654321, its place value is 4000 (thousands). 3. **Calculating the Decrease in Place Value**: - As we move one place to the right, the place value of the digit decreases by a factor of 10. - For example, moving from 4 (thousands) to 3 (hundreds), the place value changes from 4000 to 300. 4. **General Rule**: - The general rule is that the place value decreases by 10 times for each move from left to right. - Therefore, if you start with a place value of \( x \), after moving one place to the right, the new place value will be \( \frac{x}{10} \). 5. **Conclusion**: - Thus, we can conclude that the place value of a digit decreases by **10 times** as it moves place by place from left to right.
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