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State 'T' for true and 'F' for false
(I) Rounding off 2560 to the nearest thousands, gives 2000
(II) Place value of 9 in 974304200 is ninety crore.
(III) 1 lakh=1000 thousand
(IV) Roman numeral for the smallest 4-digit number is M.

A

`{:(I,II,III,IV),(T,F,T,F):}`

B

`{:(I,II,III,IV),(F,F,T,T):}`

C

`{:(I,II,III,IV),(I,T,T,T):}`

D

`{:(I,II,III,IV),(F,T,F,T):}`

Text Solution

AI Generated Solution

The correct Answer is:
Let's analyze each statement step by step to determine if they are true (T) or false (F). **Statement (I): Rounding off 2560 to the nearest thousands gives 2000.** 1. To round off a number to the nearest thousand, we look at the hundreds place. 2. The number 2560 has '5' in the hundreds place. 3. Since '5' is equal to or greater than 5, we round up. 4. Therefore, 2560 rounded to the nearest thousand is 3000. **Conclusion for (I):** This statement is **False (F)**. --- **Statement (II): Place value of 9 in 974304200 is ninety crore.** 1. In the number 974304200, we identify the position of '9'. 2. The number can be broken down as follows: - 9 is in the crore place (10^7). 3. Therefore, the place value of 9 is 9 x 10^7, which equals 90,000,000 or ninety crore. **Conclusion for (II):** This statement is **True (T)**. --- **Statement (III): 1 lakh = 1000 thousand.** 1. We know that 1 lakh is equal to 100,000. 2. Since 1 thousand is equal to 1,000, we can convert lakh to thousands: - 1 lakh = 1000 x 100 = 1000 thousand. 3. Therefore, the statement is correct. **Conclusion for (III):** This statement is **True (T)**. --- **Statement (IV): Roman numeral for the smallest 4-digit number is M.** 1. The smallest 4-digit number is 1000. 2. In Roman numerals, 1000 is represented as 'M'. 3. Therefore, the statement is correct. **Conclusion for (IV):** This statement is **True (T)**. --- ### Final Answers: - (I) F - (II) T - (III) T - (IV) T ### Summary: The final answers are: - (I) F - (II) T - (III) T - (IV) T ---
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