Subtract the largest 4-digit even positive integer from the largest 5-digit odd negative integer?

Options

A. `19999`
B. `19998`
C. `-19998`
D. `-19999`

Answer

To solve the problem of subtracting the largest 4-digit even positive integer from the largest 5-digit odd negative integer, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Largest 4-Digit Even Positive Integer:**
- The largest 4-digit number is 9999.
- Since we need an even number, we subtract 1 from 9999 to get 9998.
- Therefore, the largest 4-digit even positive integer is **9998**.

2. **Identify the Largest 5-Digit Odd Negative Integer:**
- The smallest 5-digit positive integer is 10000.
- The largest 5-digit odd negative integer is the negative of the smallest 5-digit positive integer minus 1, which is -10001.
- Therefore, the largest 5-digit odd negative integer is **-10001**.

3. **Set Up the Subtraction:**
- We need to subtract the largest 4-digit even positive integer (9998) from the largest 5-digit odd negative integer (-10001).
- This can be expressed as:
\[ -10001 - 9998 \]

4. **Perform the Subtraction:**
- Since both numbers are negative, we can add their absolute values:
\[ |-10001| + |9998| = 10001 + 9998 = 19999 \]
- The result will be negative because we are subtracting a positive number from a negative number:
\[ -19999 \]

5. **Final Answer:**
- Therefore, the result of subtracting the largest 4-digit even positive integer from the largest 5-digit odd negative integer is **-19999**.