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A pasta recipe requires 2(2)/(3)kg chee...

A pasta recipe requires `2(2)/(3)kg` cheese. Approximately, how much pasta can be made from a 21 kg cheese ?

A

`7(7)/(8)`

B

`7(4)/(8)`

C

`6(7)/(8)`

D

`6(4)/(8)`

Text Solution

AI Generated Solution

The correct Answer is:
To find out how much pasta can be made from 21 kg of cheese when the recipe requires \(2 \frac{2}{3}\) kg of cheese, we can follow these steps: ### Step 1: Convert the mixed fraction to an improper fraction. The mixed fraction \(2 \frac{2}{3}\) can be converted to an improper fraction. To do this: 1. Multiply the whole number (2) by the denominator (3): \[ 2 \times 3 = 6 \] 2. Add the numerator (2) to this result: \[ 6 + 2 = 8 \] 3. Place this result over the original denominator (3): \[ 2 \frac{2}{3} = \frac{8}{3} \] ### Step 2: Determine how many times the recipe can be made with 21 kg of cheese. Now, we need to find out how many times \( \frac{8}{3} \) kg fits into 21 kg. We do this by dividing 21 by \( \frac{8}{3} \). To divide by a fraction, we multiply by its reciprocal: \[ 21 \div \frac{8}{3} = 21 \times \frac{3}{8} \] ### Step 3: Perform the multiplication. Now we can calculate: \[ 21 \times \frac{3}{8} = \frac{21 \times 3}{8} = \frac{63}{8} \] ### Step 4: Convert the improper fraction to a mixed number. Next, we convert \( \frac{63}{8} \) to a mixed number: 1. Divide 63 by 8: \[ 63 \div 8 = 7 \quad \text{(whole number)} \] Remainder: \[ 63 - (8 \times 7) = 63 - 56 = 7 \] 2. So, \( \frac{63}{8} \) can be expressed as: \[ 7 \frac{7}{8} \] ### Final Answer: Therefore, from 21 kg of cheese, approximately \( 7 \frac{7}{8} \) pasta recipes can be made. ---
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