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If the area of a rectangle is equal to t...

If the area of a rectangle is equal to the area of a square and length of the rectangle is equal to the perimeter of the square, then the breadth of rectangle is ____

A

Side +2

B

`("Side")^(2) +2`

C

Side `div 4`

D

Side `div 3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between the rectangle and the square based on the information given. ### Step-by-Step Solution: 1. **Define the variables:** Let the side of the square be \( s \). The area of the square is given by: \[ \text{Area of square} = s^2 \] 2. **Establish the area of the rectangle:** Let the length of the rectangle be \( l \) and the breadth be \( b \). The area of the rectangle is given by: \[ \text{Area of rectangle} = l \times b \] 3. **Set the areas equal:** According to the problem, the area of the rectangle is equal to the area of the square: \[ l \times b = s^2 \] 4. **Define the perimeter of the square:** The perimeter \( P \) of the square is given by: \[ P = 4s \] 5. **Set the length of the rectangle equal to the perimeter of the square:** According to the problem, the length of the rectangle is equal to the perimeter of the square: \[ l = 4s \] 6. **Substitute the value of \( l \) in the area equation:** Substitute \( l = 4s \) into the area equation: \[ 4s \times b = s^2 \] 7. **Solve for \( b \):** To find \( b \), divide both sides of the equation by \( 4s \): \[ b = \frac{s^2}{4s} \] Simplifying this gives: \[ b = \frac{s}{4} \] ### Final Answer: The breadth of the rectangle is \( \frac{s}{4} \).
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