On one day, the temperature on a hill at 8 pm. Was `2"^(@)C` but at mid-night, it fell down to `-3"^(@)C`. By how much did the temperature fall?

Options

A. `5"^(@)C`
B. `6"^(@)C`
C. `7"^(@)C`
D. `8"^(@)C`

Answer

To find out how much the temperature fell from 2°C to -3°C, we can follow these steps:

### Step 1: Identify the initial and final temperatures.
- Initial temperature at 8 PM = 2°C
- Final temperature at midnight = -3°C

### Step 2: Calculate the difference in temperature.
To find the fall in temperature, we subtract the final temperature from the initial temperature:
\[ \text{Fall in temperature} = \text{Initial temperature} - \text{Final temperature} \]
Substituting the values:
\[ \text{Fall in temperature} = 2°C - (-3°C) \]

### Step 3: Simplify the expression.
Subtracting a negative number is the same as adding its positive:
\[ \text{Fall in temperature} = 2°C + 3°C = 5°C \]

### Conclusion:
The temperature fell by 5°C.