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Niharika walks thrice around a square f...

Niharika walks thrice around a square field of side 22 m . Girish walks twice around a rectangular field of length 10 m and breadth 12 m . Who covers more distance and by how much?

A

Girish , 20 m

B

Niharika ,200 m

C

Girish ,176 m

D

Niharika ,176 m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the distances covered by Niharika and Girish and then compare them. ### Step 1: Calculate the distance covered by Niharika Niharika walks around a square field with a side length of 22 meters. 1. **Find the perimeter of the square field:** \[ \text{Perimeter (P)} = 4 \times \text{side} = 4 \times 22 = 88 \text{ meters} \] 2. **Since Niharika walks thrice around the square field, the total distance covered by her is:** \[ \text{Distance covered by Niharika} = 3 \times \text{Perimeter} = 3 \times 88 = 264 \text{ meters} \] ### Step 2: Calculate the distance covered by Girish Girish walks around a rectangular field with a length of 10 meters and a breadth of 12 meters. 1. **Find the perimeter of the rectangular field:** \[ \text{Perimeter (P)} = 2 \times (\text{Length} + \text{Breadth}) = 2 \times (10 + 12) = 2 \times 22 = 44 \text{ meters} \] 2. **Since Girish walks twice around the rectangular field, the total distance covered by him is:** \[ \text{Distance covered by Girish} = 2 \times \text{Perimeter} = 2 \times 44 = 88 \text{ meters} \] ### Step 3: Compare the distances Now we compare the distances covered by Niharika and Girish. 1. **Distance covered by Niharika:** \[ 264 \text{ meters} \] 2. **Distance covered by Girish:** \[ 88 \text{ meters} \] 3. **Difference in distance:** \[ \text{Difference} = \text{Distance covered by Niharika} - \text{Distance covered by Girish} = 264 - 88 = 176 \text{ meters} \] ### Conclusion Niharika covers more distance than Girish by 176 meters.
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