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Find the missing number : 16 + 1(1/6)...

Find the missing number :

`16 + 1(1/6) + 33 + 1(1/6) = 15(1/2) +` ?

A

`26(1/2)`

B

51

C

`57(1/2)`

D

`66(1/2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the missing number in the equation: \[ 16 + 1\frac{1}{6} + 33 + 1\frac{1}{6} = 15\frac{1}{2} + ? \] Let's break it down step by step. ### Step 1: Convert Mixed Numbers to Improper Fractions First, we convert the mixed numbers into improper fractions for easier calculations. 1. \( 1\frac{1}{6} = \frac{6 \times 1 + 1}{6} = \frac{7}{6} \) 2. \( 15\frac{1}{2} = \frac{2 \times 15 + 1}{2} = \frac{31}{2} \) Now, rewrite the equation: \[ 16 + \frac{7}{6} + 33 + \frac{7}{6} = \frac{31}{2} + ? \] ### Step 2: Combine Like Terms on the Left Side Next, we combine the whole numbers on the left side: 1. \( 16 + 33 = 49 \) So the equation now looks like: \[ 49 + \frac{7}{6} + \frac{7}{6} = \frac{31}{2} + ? \] ### Step 3: Add the Fractions on the Left Side Now, add the fractions: 1. \( \frac{7}{6} + \frac{7}{6} = \frac{14}{6} = \frac{7}{3} \) Now the equation is: \[ 49 + \frac{7}{3} = \frac{31}{2} + ? \] ### Step 4: Convert Whole Number to Fraction Convert 49 into a fraction with a common denominator. The least common multiple of 3 and 2 is 6. 1. \( 49 = \frac{49 \times 6}{6} = \frac{294}{6} \) 2. \( \frac{7}{3} = \frac{7 \times 2}{6} = \frac{14}{6} \) Now combine them: \[ \frac{294}{6} + \frac{14}{6} = \frac{308}{6} \] ### Step 5: Convert \( \frac{31}{2} \) to a Fraction with Denominator 6 Convert \( \frac{31}{2} \) to a fraction with a denominator of 6: 1. \( \frac{31}{2} = \frac{31 \times 3}{2 \times 3} = \frac{93}{6} \) ### Step 6: Set Up the Equation Now we have: \[ \frac{308}{6} = \frac{93}{6} + ? \] ### Step 7: Solve for the Missing Number To find the missing number, subtract \( \frac{93}{6} \) from \( \frac{308}{6} \): \[ ? = \frac{308}{6} - \frac{93}{6} = \frac{308 - 93}{6} = \frac{215}{6} \] ### Step 8: Convert Back to Mixed Number Convert \( \frac{215}{6} \) back to a mixed number: 1. Divide 215 by 6, which gives 35 with a remainder of 5. 2. So, \( \frac{215}{6} = 35\frac{5}{6} \) ### Final Answer Thus, the missing number is: \[ 35\frac{5}{6} \] ---
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