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In the given figure, DeltaABC~DeltaDCB, ...

In the given figure, `DeltaABC~DeltaDCB`, then `ABxxDB` =

A

`OAxxOD`

B

`OBxxOC`

C

`ABxxDC`

D

`DCxxAC`

Text Solution

Verified by Experts

The correct Answer is:
D
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