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In the given figure, AD | BC, BE | AC, C...

In the given figure, AD `_|_` BC, BE `_|_` AC, CF `_|_` AB, then `AF^(2)+BD^(2)+CE^(2)` =

A

`OA^(2)+OB^(2)+OC^(2)`

B

`OD^(2)+OE^(2)+OF^(2)`

C

`AB^(2)+BC^(2)+AC^(2)`

D

`AE^(2)+BF^(2)+CD^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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