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A can build a wall in 25 days and B can ...

A can build a wall in 25 days and B can demolish the same wall in 80 days and C can build the same wall in 60 days. If they work on consecutive days one after another starting from A on the first day. Then, in how many days will the work be completed?

A

67 days

B

`67 (17)/(24)` days

C

`66 (17)/(24)` days

D

`68 (17)/(24)` days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we first need to determine the work done by A, B, and C in one day. 1. **Calculate the work done by A in one day:** - A can build the wall in 25 days. - Therefore, the work done by A in one day = 1/25 of the wall. 2. **Calculate the work done by B in one day:** - B can demolish the wall in 80 days. - Therefore, the work done by B in one day = -1/80 of the wall (negative because B is demolishing). 3. **Calculate the work done by C in one day:** - C can build the wall in 60 days. - Therefore, the work done by C in one day = 1/60 of the wall. 4. **Determine the total work done in a 3-day cycle (A, B, C):** - Day 1 (A): Work done = 1/25 - Day 2 (B): Work done = -1/80 - Day 3 (C): Work done = 1/60 - Total work done in 3 days = (1/25) + (-1/80) + (1/60) 5. **Find a common denominator to add the fractions:** - The least common multiple (LCM) of 25, 80, and 60 is 600. - Convert each fraction: - 1/25 = 24/600 - -1/80 = -7.5/600 - 1/60 = 10/600 - Total work done in 3 days = 24/600 - 7.5/600 + 10/600 - = (24 - 7.5 + 10) / 600 - = 26.5 / 600 - = 53/1200 of the wall in 3 days. 6. **Calculate how many cycles are needed to complete the wall:** - To find out how many cycles (3 days) are needed to complete the wall, we need to find how many times 53/1200 fits into 1 (the whole wall). - Number of cycles = 1 / (53/1200) = 1200/53 ≈ 22.64 cycles. 7. **Calculate the total days to complete the wall:** - Each cycle takes 3 days. - Total days = 22 cycles * 3 days/cycle = 66 days. - Since we need to complete the wall, we will consider the remaining work after 22 cycles. 8. **Calculate the remaining work after 66 days:** - Work done in 66 days = 22 cycles * (53/1200) = 1166/1200. - Remaining work = 1 - 1166/1200 = 34/1200 = 17/600. 9. **Determine how many more days are needed to complete the remaining work:** - After 66 days, it will be A's turn again (Day 67). - A's work on Day 67 = 1/25. - Convert 1/25 to the common denominator of 600 = 24/600. - Remaining work = 17/600. - Since A can complete 24/600 in one day, he will finish the remaining work on Day 67. 10. **Final calculation of total days:** - Total days = 66 days (for 22 cycles) + 1 day (to complete the remaining work) = 67 days. Thus, the total number of days required to complete the work is **67 days**.
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