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If the polynomial f(x) = ax^3 + bx - c i...

If the polynomial `f(x) = ax^3 + bx - c` is exactly divisible by the polynomial `g(x) = x^(2) + bx + c, cne0`, then which of the following options is true?

A

`c=2b^2`

B

`ab=1`

C

`ac=2b`

D

All of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the relationship between the coefficients of the polynomial \( f(x) = ax^3 + bx - c \) and the polynomial \( g(x) = x^2 + bx + c \) given that \( f(x) \) is exactly divisible by \( g(x) \). ### Step-by-Step Solution: 1. **Understanding Divisibility**: Since \( f(x) \) is exactly divisible by \( g(x) \), we can express this relationship as: \[ f(x) = g(x) \cdot q(x) \] where \( q(x) \) is some polynomial. Given the degrees of the polynomials, \( f(x) \) is of degree 3 and \( g(x) \) is of degree 2. Therefore, \( q(x) \) must be of degree 1 (since \( 2 + 1 = 3 \)). 2. **Expressing \( q(x) \)**: Let \( q(x) = mx + n \), where \( m \) and \( n \) are constants. 3. **Expanding the Product**: We can expand \( f(x) \) as follows: \[ f(x) = g(x) \cdot q(x) = (x^2 + bx + c)(mx + n) \] Expanding this gives: \[ = mx^3 + nx^2 + bmx^2 + bnx + cmx + cn \] Combining like terms, we get: \[ = mx^3 + (n + bm)x^2 + (bn + cm)x + cn \] 4. **Setting Coefficients Equal**: For \( f(x) = ax^3 + bx - c \) to hold, the coefficients of the corresponding powers of \( x \) must be equal. Thus, we can set up the following equations: - Coefficient of \( x^3 \): \( m = a \) - Coefficient of \( x^2 \): \( n + bm = 0 \) - Coefficient of \( x^1 \): \( bn + cm = b \) - Constant term: \( cn = -c \) 5. **Solving the Equations**: From the constant term equation \( cn = -c \), since \( c \neq 0 \), we can divide both sides by \( c \): \[ n = -1 \] Substituting \( n = -1 \) into the second equation \( n + bm = 0 \): \[ -1 + bm = 0 \implies bm = 1 \implies b = \frac{1}{m} \] Now substituting \( m = a \): \[ b = \frac{1}{a} \] Finally, substituting \( n = -1 \) and \( m = a \) into the third equation \( bn + cm = b \): \[ b(-1) + ca = b \implies -b + ca = b \implies ca = 2b \] 6. **Final Relationships**: We have derived the relationships: - \( b = \frac{1}{a} \) - \( ca = 2b \) ### Conclusion: From the relationships derived, we can conclude that the coefficients \( a \), \( b \), and \( c \) are related such that \( ca = 2b \) and \( b = \frac{1}{a} \).
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