`int 1/(1-tanx)dx`

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Evaluate: int1/(1-tanx)\ dx

(i) int(tanx)/((sec x +tanx))dx , (ii) int(1)/((1-sinx))dx

int ((1+tanx)/(1-tanx))dx

int((1+tanx)/(1-tanx))dx

Evaluate the following integral: int_0^(pi//2)1/(1+tanx)dx

int_(-pi//4)^0 (1+tanx)/(1-tanx) dx

int(1-tanx)/(1+tanx)dx=

int(1-tanx)(1+tanx)dx

(i) int (1-tanx)/(1+tanx) dx (ii) int (1- cot x)/(1+ cot x) dx

int((1+tan)/(1-tanx))^(2)dx=