Simplify `sqrt((x+3)^2+(y-4)^2)=sqrt((x-5)^2+(y-6)^2)`

Simplify: 5 (x + 3y) -2 (3x-4y)

Simplify : (sqrt(x^(2)+y^(2))-y)/(x-sqrt(x^(2)-y^(2)))-:(sqrt(x^(2)-y^(2))+x)/(sqrt(x^(2)+y^(2))+y)

Equation sqrt((x-5)^(2)+y^(2))+sqrt((x+5)^(2)+y^(2))=20 represents

The equation sqrt((x-4)^(2)+y^(2))+sqrt((x+4)^(2)+y^(2))=6 represents

Assuming that x,y,z are positive real numbers,simplify each of the following: (sqrt(x^(-3)))^(5) (ii) (sqrt(x))^(-(2)/(3))sqrt(y^(4))-:sqrt(xy^(-(1)/(2)))

Simplify (a) (sqrt(5)+sqrt(3))/(sqrt(2)) +2 (b) (sqrt3+sqrt2)/(sqrt3+sqrt6)-4

A vertex of an equilateral triangle is at (2, 3), and th equation of the opposite side is x+y=2 , then the equaiton of the other two sides are (A) y=(2+sqrt(3)) (x-2), y-3=2sqrt(3)(x-2) (B) y-3=(2+sqrt(3) (x-2), y-3= (2-sqrt(3) (x-2) (C) y+3=(2-sqrt(3)(x-2), y-3=(2-sqrt(3) (x+2) (D) none of these

Simplify: 5+[x-{2y-(6x+y-4)+2x^2}-(x^2-2y)]

sqrt(2)x + sqrt(3)y=0 sqrt(5)x - sqrt(2)y=0