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"(d)/(dx)(sin x+cos t)="...

"(d)/(dx)(sin x+cos t)="

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d/(dx) (sin x+ cos x)

The differentiation of sin x with respect to x is cos x* i.e.(d)/(dx)(sin x)=cos x

why (d)/(dx)sin x=cos x?

(d)/(dx)[(sin x)/(1+cos x)]=

(d)/(dx)sin^(2)x

(d)/(dx)(log*sin x)

(d)/(dx)cos^(-1)(sin x)=

(d)/(dx)sin(x^(x))

(d) / (dx) (sin x) / (sqrt (1 + cos x))

(d)/(dx)(sin^(-1)x+cos^(-1)x) is equal to