`x^y.y^x=a`, then `(dy)/(dx)`=?

If x^y=y^x ,then find (dy)/(dx)

If x^(y)=e^(x-y) , then (dy)/(dx) is equal to

If x^y=e^(x-y) , then (dy)/(dx) is (a) (1+x)/(1+logx) (b) (1-logx)/(1+logx) (c) not defined (d) (logx)/((1+logx)^2)

If x^y+y^x=2, find (dy)/(dx) .

If tan(x+y)=e^(x+y) , then (dy)/(dx)

If x^y=y^x , find (dy)/(dx) .

If y^x+x^y+x^x=a^b , find (dy)/(dx) .

If x^(y)+y^(x)=1 then find (dy)/(dx)

If If x^(y)+y^(x)=1 then find (dy)/(dx) .

If x^y. y^x=1 , prove that (dy)/(dx)=-(y(y+xlogy))/(x(ylogx+x))