Simplify `sec^2theta-tan^2theta+1`

sec^(2)theta=1-tan2 theta

Simplify sec theta[[tan theta,sec theta],[sec theta,-tan theta]] - tan theta[[sec theta,tan theta],[tan theta,-sec theta]]

Find the value of theta if sec^2theta+tan^2theta=1

(sec^(2)theta-1)/(tan^(2)theta)=?

The value of (sec^2 theta(2+tan^2 theta +cot^2 theta) div (sin^2 theta-tan^2 theta))/((cosec^2 theta+sec^2 theta)(1+ cot^2 theta)^2) is: (sec^2 theta(2+tan^2 theta +cot^2 theta) div (sin^2 theta-tan^2 theta))/((cosec^2 theta+sec^2 theta)(1+ cot^2 theta)^2) का मान ज्ञात कीजिए?

Prove that quad (sin theta-cos theta+1)/(sin theta+cos theta-1)=(1)/(sec theta-tan theta) ,using the identity sec^(2)theta=1+tan^(2)theta

Prove that- sec^2theta-1-tan^2theta=0

What is the simplified value of [(1+sec 2theta)tan^(2)theta]+1 ?

The determinant |(sec^(2)theta, tan^(2)theta,1),(tan^(2)theta, sec^(2)theta, -1),(12,10,2)| equals