Solve `sec^2theta+tan^2theta=1`

Find the value of theta if sec^2theta+tan^2theta=1

sec^(2)theta=1-tan2 theta

(1-cos^2theta)sec^2 theta= tan^2 theta

The determinant |(sec^(2)theta, tan^(2)theta,1),(tan^(2)theta, sec^(2)theta, -1),(12,10,2)| equals

Prove that- sec^2theta-1-tan^2theta=0

Solve: 1+ tan^(2) theta = ? A. cos^(2) theta B. sec^(2) theta C. tan^(2) theta D. 2

Solve 3(sec^(2) theta+tan^(2) theta)=5 .

Prove :sec^(6)theta=tan^(6)theta+3tan^(2)theta sec^(2)theta+1

The value of (sec^2 theta(2+tan^2 theta +cot^2 theta) div (sin^2 theta-tan^2 theta))/((cosec^2 theta+sec^2 theta)(1+ cot^2 theta)^2) is: (sec^2 theta(2+tan^2 theta +cot^2 theta) div (sin^2 theta-tan^2 theta))/((cosec^2 theta+sec^2 theta)(1+ cot^2 theta)^2) का मान ज्ञात कीजिए?