∫ x e x ( 1 + x ) 2 d x

int(e^x)/((1+e^x)(2+e^x))dx

(xe^x)/(1+x)^2dx= (A) e^x/(1+x) (B) e^x/(1+x)^2 (C) e^xlog(1+x) (D) none of these

Evaluate ∫ x 2 e x 2 ( 2 x ) d x .

int((1+(log)_e x)^2)/(1+(log)_e x^(x+1)+((log)_e x^(sqrt(x)))^2)dx=

int e^x((x^2+1))/((x+1)^2)dx is equal to ((x-1)/(x+1))e^x+c (b) e^x((x+1)/(x-1))+c e^x(x+1)(x-1)+c (d) none of these

int(1+2x^(2)+(1)/(x))e^(x^(2)-(1)/(x))dx is equal to (a) -x e^(x^(2)-(1)/(x))+c (b) x e^(x^(2)-(1)/(x))+c (c) (2x-1) e^(x^(2)-(1)/(x))+c (d) (2x+1) e^(x^(2)-(1)/(x))+c

int(e^x(1+x))/(cos^2(x e^x))\ dx= (a) 2(log)_ecos(x e^x)+C (b) sec(x e^x)+C (c) tan(x e^x)+C (d) tan(x+e^x)+C

int(x-1)\ e^(-x)\ dx is equal to x e^x+C (b) x e^x+C (c) -x e^(-x)+C (d) x e^(-x)+C

The value of the integral int_-a^a (x e^(x^2))/(1+x^2)dx is (A) e^(a^2) (B) 0 (C) e^(-a^2) (D) a

int(e^(2x)+2e^x-e^(-x)-1)e^(e^x+e^(-x))dx=g(x)e^(e^x+e^(-x)) , then find g(0) .