find the value of `k` if `A=[[1,1,-1,1],[1,-1,k,-1],[3,1,0,1]]`

Find the value off sum_(k=1)^10(2+3^k)

Using vectors, find the value of k, such that the points (k,-10, 3), (1,-1, 3) and (3, 5, 3) are collinear.

Find the values of k for which the points (2k ,3k),(1,0),(0,1),a n d(0,0) lie on a circle.

If overline(P_1P_2) is perpendicular to overline(P_2P_3) , then the value of k is, where P_1(k, 1, -1), P_2(2k, 0, 2) and P_3(2+2k, k, 1) is …..

(i) If the points (1,4),(3,-2)and (k,1) are collinear, fine the value of k. (ii) If the points A(k+1,2k),B(3k,2k+3)andC(5k-1,5k) are collinear, then find k

Find the value of k for which (1, 1), (3, 2) (4, k) is collinear.

Find the values of k for which (k+1)x^2-2(3k+1)x+8k+1=0 has real and equal roots.

If [2 1 3] [{:(-1,0,-1),(-1,1,0),(0,1,1):}][{:(1),(0),(-1):}] =A, then find the value of A.

Find the value of k , for which f(x)={((sqrt(1+k x)-\ sqrt(1-k x))/(x) , if -1lt=x<0),( (2x+1)/(x-1), 0lt=x<1):} is continuous at x=0

Find the value of k , for which f(x)={(sqrt(1+k x)-\ sqrt(1-k x))/(x) "if",\ -1lt=x<0"(2x+1)/(x-1\ ) if"\ 0lt=x<1 is continuous at x=0