The speed of a train is reduced from 60km/h to 15 km/h, while it travels a distance of 450m. If the retardation is uniform, find how much further it will travel before coming to rest?

Explanation

`a= v^(2)-u^(2)"/"2s= (25"/"6)^(2)- (50"/"3)^(2)"/"2xx 450, a= -0.289 m"/"s^(2)`.
Distance travelled before coming to rest `= v^(2)"/"2a= (25"/"6)^(2)"/"2 xx 0.289= 30m`.