A rocket is fired vertically up from the ground with a resultant vertical acceleration of `10 m//s^2.` The fuel is finished in 1 min and it continues to move up. (a) What is the maximum height reached? (b) Afte2r how much time from then will the maximum height be reached?(Take `g= 10 m//s^2`)

Explanation

`u=0, a= 10ms^(-2)` for t= 1 min = 60s, `v_(1)= u+ at= 0+10xx 60= 600 ms^(-1)` when the fuel exhaust it moves against gravity `a= -9.8 m"/"s^(2)` at the maximum height `v_(2)= 0, v_(2)= 600-9.8xxt , t= 600"/"9.8= 61.2s`.