If a person can throw a stone to the maximum height of h metre vertically, then the maximum horizontal distance through which the stone can be thrown by the same person is

Explanation

At maximum height `v= 0, 0-v_(0)^(2) = -2gH`
Maximum range `R_("max")= (v_(0)^(2))/(g)= 2H" "H= (v_(0)^(2))/(g)`.