A particle of mass `4kg` executes `SHM` such that its energy of `SHM` is `36J`.Its velocity at `t=0` is `-3`m/s and displacement from the mean position is `+20cm`.The equation of its motion is:

A body of mass 1 gram executes a linear S.H.M. of period 1.57 s. If its maximum velocity is 0.8 m/s, then its maximum displacement from the mean position is

A body of mass 5g is executing SHM with amplitude 10cm , its velocity is 100cm//s . Its velocity will be 50cm//s at a displacement from the mean position equal to

A particle executing S.H.M. is given by x=10sin(8t+pi//3)m . Its velocity when it is at a distance 6 m from the mean position is,

A partical executes SHM on a straigh line path. The amplitude of oscillation is 2cm. When the displacement of the particle from the mean position is 1cm, the magnitude of its acceleration is equal to that of its velocity. Find the time period of SHM, also the ms. velocity and ms. acceleration of SHM.

A body executes SHM has its velocity 10cm//s and 7cm//s when its displacements from mean positions are 3cm and 4cm respectively. The length of path is nearly

A particle of mass 2kg executing SHM has amplitude 20cm and time period 1s. Its maximum speed is

A particle of mass m executing S.H.M. about its mean position. The total energy of the particle at given instant is

A particle of mass m is executing SHM about its mean position. The total energy of the particle at given instant is

A particle executes SHM of amplitude A. At what distance from the mean position is its KE equal to its PE ?

A point particle of mass 0.1kg is executing SHM with amplitude of 0.1m . When the particle passes through the mean position. Its K.E. is 8xx10^(-3)J . Obtain the equation of motion of this particle if the initial phase of oscillation is 45^(@) .