5.Two moving coil galvanometers `G_(1)` and `G_(2)` have the following particulars respectively : `N_(1)=30,A_(1)=3*6times10^(-3)m^(2),B_(1)=0.25T` `N_(2)=42,A_(2)=1.8times10^(-3)m^(2),B_(2)=0*50T` . The spring constant is same for both the galvanometers.The ratio of current sensitivities of `G_(1)` and `G_(2)` is :

Two moving coil meters, M_(1) and M_(2) have following particulars : R_(1)=10Omega,N_(1)=30,A_(1) =3.6xx10^(-3)m^(2),B_(1)=0.25T R_(2)=10Omega,N_(2)=42,A_(2) =1.8xx10^(-3)m^(2),B_(2)=0.50T ( The spring constants are identical for two meters ) . The ration of (i) current sensitivity (ii) voltage sensitivity of M_(2) and M_(1) is

Two moving coil metres M_(1) and M_(2) have the following particular R_(1) =10Omega, N_(1) =30, A_(1) = 3.6 xx 10^(-3) m^(2), B_(1) =0.25 T, R_(2) = 14Omega , N_(2) =42, A_(2) = 1.8 xx 10^(-3) m^(2), B_(2) =0.50 T The spring constants are identical for the two metres. What is the ratio of current sensitivity and voltage sensitivity of M_(2)" to" M_(1)?

Two moving coil meters M_1 and M_2 have the following particulars: R_1=10Omega , N_1=30 , A_1=3*6xx10^-3m^2 , B_1=0*25T , R_2=14Omega , N_2=42 , A_2=1*8xx10^-3m^2 , B_2=0*50T (The spring constants are identical for the two metres). Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M_2 and M_1 .

Two moving coil galvanometers A and B have rectangular coil of 100 turns each. The area of coil of galvanometers A and B are 2 xx 10^(-4) m^(2) " and " 6 xx 10^(-4) m^(2) respectively. Calculate the ratio of current sensitivity of A to B if coils in both salvanometers are kept in a radial horizontal magnetic field of 0.2 T and the torsional constant of hair springs are also same.

If a is the A.M.of b and c and the two geometric mean are G_(1) and G_(2), then prove that G_(1)^(3)+G_(2)^(3)=2ab

Compare the current sensitivity and voltage sensitivity of the following moving coil galvanometers: Meters A : n=30, A=1*5xx10^-3m^2 , B=0*25T, R=20Omega Meter B: n=35, A=2*0xx10^-3m^2 , B=0*25T, R=30Omega . You are given that the springs in the two meters have the same torsional constants.

If a is the A.M.of b and c and the two geometric means are G_(1) and G_(2), then prove that G_(1)^(3)+G_(2)^(3)=2abc.

If A_(1) ,be the A.M.and G_(1),G_(2) be two G.M.'s between two positive numbers then (G_(1)^(3)+G_(2)^(3))/(G_(1)G_(2)A_(1)) is equal to: