`int_0^9(3x-6)/2dx`

int_0^2(3x^2-4)dx

int_0^1 e^(2-3x)dx

Evaluate: int_0^1(3x^2+5x)dx

Evaluate: int_0^1 1/(2x-3)dx

Evaluate the following integrals : int_0^2(x+3)dx

int_0^1(2-3x+x^2)dx

If f(x) is continuous and int_(0)^(9)f(x)dx=4 , then the value of the integral int_(0)^(3)x.f(x^(2))dx is

int_0^9{sqrt(x)}dx , where {x} denotes the fractional part of x , is 5 (b) 6 (c) 4 (d) 3

int_0^5(x^2+3x)dx =

The area of the region for which is int_1^3(3-2x-x^2)dx (b) int_0^3(3-2x-x^2)dx int_0^1(3-2x-x^2)dx (d) int_(-1)^3(3-2x-x^2)dx 0 0