`int_0^2(3x+1)(x-1)dx`

int_-a^a(1+x^3)^(-1)dx= (A) 0 (B) 2int_0^a(1-x^6)^(-1)dx (C) 2int_0^a(1+x^3)^(-1)dx (D) 2int_0^a[1+(a-x^3)]^(-1)dx

Evaluate: int_0^4 1/(x+sqrt(x))dx (ii) int_0^1(2x)/(5x^2+1)dx

Evaluate: int_0^1 1/(2x-3)dx

int_0^1 (x/(x+1))dx

int_(0)^(3)(x^(2)+1)dx

The value of ("^n C_0)/n + ("^nC_1)/(n+1) + ("^nC_2)/(n+2) +....+ ("^nC_ n)/(2n) is equal to a. int_0^1x^(n-1)(1-x)^n dx b. int_1^2x^n(x-1)^(n-1)dx c. int_1^2x^(n-1)(1+x)^n dx d. int_0^1(1-x)^(n-1)dx

int_0^2 |1-x|dx

int_0^4 (2x-1) dx

The value of int_(0)^(1)({2x}-1)({3x}-1)dx , (where {} denotes fractional part opf x) is equal to :

The value of int_0^(2) (3x ^ 2 −1)dx