`int_0^(5)(2-x)dx`

int_0^5e^(-2x)dx

int_0^(2a)f(x)dx is equal to 2int_0^af(x)dx b. 0 c. int_0^af(x)dx+int_0^af(2a-x)dx d. int_0^af(x)dx+int_0^(2a)f(2a-x)dx

int_0^5 (x-1)dx

int_0^5 (x+1)dx

Show that int_(0)^(2)(2x+1)dx = int_(0)^(5)(2x+1)+int_(5)^(2)(2x+1)

prove that : int_(0)^(2a) f(x)dx = int_(0)^(a) f(x)dx + int_(0)^(a)f(2a-x)dx

int_(0)^(a)f(2a-x)dx=m and int_(0)^(a)f(x)dx=n then int_(0)^(2a)f(x)dx is equal to

Let f(x)=f(a-x) and g(x)+g(a-x)=4 then int_0^af(x)g(x)dx is equal to (A) 2int_0^af(x)dx (B) int_0^af(x)dx (C) 4int_0^af(x)dx (D) 0

(i) int_0^4 (2x+3) dx (ii) int_0^4 (2x-1)dx

Evaluate int_(0)^(5)(x^2+3x)dx