`11^m -: 11^-3=11^5`

11^x/11^3=11^2

11^x/11^3=11^2 What would be the value of x ?

7/11+(-3)/11

""^11C_0^2 - ""^11C_1^2 + ""^11C_2^2 - ""^11C_3^2 + ……- "^11C_11^2 =

The minimum temperature (in ""^(@)C ) during the day at Delhi has been recorded for 30 days, as given below: 11.8, 11.6, 11.6, 11.4, 11.3, 11.4, 11.7, 11.7, 11.3, 11.4, 11.7, 11.7, 11.6, 11.3, 11.5, 11.8, 11.3, 11.3, 11.4, 11.5, 11.3, 11.5, 11.5, 11.8, 11.5, 11.4, 11.3, 11.6, 11.5 Construct a frequency table for the above data.

If A=[(1,2),(3,-5)] then A^-1 is A. [(-5,-2),(-3,1)] B. [(5/11,2/11),(3/11, - 1/11)] C. [(-5/11,-2/11),(-3/11, -1/11)] D. [(5,2),(3,-1)]

If cosA=3/4, then 32 sin (A/2) sin ((5A) /2)= ------------- (A) √11 (B) -√11 (C) 11 (D) -11

Simplify: (3/11)^-5 xx (3/11)^3

Prove that tan 56^@ = (cos11^@ + sin11^@)/(cos11^@ - sin11^@)

Prove that ( cos 11^(@) + sin 11^(@))/( cos 11 ^(@) - sin 11 ^(@)) = tan 56 ^(@).