` int_1^aint_1^b( (dx.dy)/(x.y)).`

int_0^1 int_1^2 (x^2+y^2) dx dy

If y=x int_(1)^(x)ln tdt, find (dy)/(dx) at x=e

x(dy)/(dx)-y=x+1

int_0^1 int_0^sqrt(1+x^2) (dy dx)/(1+x^2+y^2)

int_0^1 int_y^sqrt(y) (x^2+y^2) dy dx=

int_(0)^(1)dx int_(0)^(x)e^((y)/(x))dy

If y=int_1^(x^3)dt/(1+t^4), find dy/dx.

The general solution of a differential equation of the type (dx)/(dy)+P_(1)x=Q_(1) is (A)ye^(int P_(1)dy)=int(Q_(1)e^(int P_(1)dy))dy+C(B)ydot e^(int P_(1)dx)=int(Q_(1)e^(int P_(1)dx))dx+C(C)xe^(int P_(1)dx)=int(Q_(1)e^(int P_(1)dx))dy+C(D)xe^(int p_(1)dx)=int Q_(1)e^(int p_(1)dx)dx+C

Solve the differential equation (dy)/(dx) = y + int_(0)^(1)y(x)dx , given that the value of y is 1, when x = 0.

y=int(x+1)/(xy)dy