Find the equivalent resistance between A and B.

Explanation

again, `R _(1) = (6 xx 3 )/( 6 + 3 ) = (18)/(9) = 2 Omega`
`R _(1) = ( 4 xx 12 )/( 4 + 12) = ( 48)/(12) = ( 48)/(16) = 3 Omega`
`R _(AB) R_(1) + R _(2) = 2 Omega + 3 Omega = 5 Omega`