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A moving coil galvanometer has a coil of...

A moving coil galvanometer has a coil of resistance `59 Omega` . It shows a full scale deflection for a current of 50 mA. How will you convert it to an ammeter having a range of 0 to 3 A?

Text Solution

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By connecting a shunt in parallel with the galvanometer
`S=(I_(g)G)/(I-I_(g))`
`=(50xx10^(-3)xx59)/(3-(50xx10^(-3)))`
`=(50xx10^(-3) xx 59)/(2.95) Omega`
`=983.33 xx 10^(-3)Omega`
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