`cos(sin^(-1)x+cos^(-1)x)=0`

Prove that sin^(-1) cos (sin^(-1) x) + cos^(-1) x) = (pi)/(2), |x| le 1

Find the value of sin^(-1)(cos(sin^(-1)x))+cos^(-1)(sin(cos^(-1)x))

Prove that the identities,sin^(-1)cos(sin^(-1)x)+cos^(-1)sin(cos^(-1)x)=(pi)/(2)|x|<=1

The value of x satisfying the equation (sin^(-1)x)^(3)-(cos^(-1)x)^(3)+(sin^(-1)x)(cos^(-1)x)(sin^(-1)x-cos^(-1)x)=(pi^(3))/(16) is :

The value of tan(sin^(-1)(cos(sin^(-1)x)))tan(cos^(-1)(sin(cos^(-1)x))), where x in(0,1) is equal to 0(b)1(c)-1(d) none of these

If sin^(-1) x + sin^(-1)y = pi//2 and cos^(-1) x - cos^(-1) y = 0 , then value x and y respectively

If y=(sin^(-1)x-cos^(-1)x)/(sin^(-1)x+cos^(-1)x)," then "(dy)/(dx)=

If sin^(-1)x+sin^(-1)(1-x)+cos^(-1)x=0 , then x is