`I=int((x+1)dx)/(x(x+logx))`

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Evaluate int((x+1)/(x))(x+logx)^(2)dx

int(logx-1)/(x)dx

int(dx)/(x.logx.log(logx))=

int(dx)/(x(3+logx))=

The value of int_(1)^(e)(dx)/(6x(logx)^(2)+7x(logx)+2x)=

int_(1//e)^(e)(dx)/(x(logx)^(1//3))

int_(1)^(2)(dx)/(x(1+logx)^(2))

int(log(logx))/(x.logx)dx=

int(1)/(x(logx))dx=?