d/dx [tan^-1 ((sqrt x-x)/(1+x^3/2)) अवकल...

`d/dx [tan^-1 ((sqrt x-x)/(1+x^3/2))` अवकलन करो

d/dx [tan^-1 ((sqrt x-x)/(1+x^3/2)) अवकलन करो
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Differentiate tan^(-1)((sqrt(1+x^(2)-1))/(x)) with respect to tan^(-1)...
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Differentiate sqrt((1-tan x)/(1+tan x)) w.r.t.x
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(d)/(dx)((1-tan x)/(1+tan x))*(d)/(dx)((1-tan x)/(1+tan x))
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(d)/(dx)[tan^-1((sqrt(1+x^(2))-1)/(x))]=
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(d)/(dx)tan^(-1)((x)/(1-sqrt(1+x^(2))))]=
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(d)/(dx)[tan{tan^(-1)((x)/(a))-tan^(-1)((x-a)/(x+a))}]=
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(d)/(dx)((1)/(3)tan^(3)x-tan x+x)=
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(d)/(dx ) { Tan ^(-1) ( sqrt(|(a -b)/(a +b)|)tan ""(x)/(2))}=
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