`int_(-2)^2 |1-k^2| dk`

int_(1)^(2)|2x-1|dx

If int_(-2)^(0) f (x) dx =k, then int_(-2)^(0) |f(x)|dx is

int _(2)^(k)(2x+1) dx = 6 then k is equal to

If int_0^(1/2)(x^2)/(1-x^2)^(3/2)dx=k/6 , then k=

If k in N and I_(k)=int_(-2kp)^(2kpi) |sin x|[sin x]dx , where [.] denotes the greatest integer function, then int_(k=1)^(100) I_(k) equal to

int _(-1//2)^(1//2) cos x log ((1+x)/(1-x)) dx = k log 2 , then k equals

If int_(1)^(2) {K^(2) + (4-4K)x+4x^(3)} dx le 12 , then which one of the following is correct ?

Let J=int_(-5)^(-4)(3-x^(2))tan(3-x^(2))dx and K=int_(-2)^(-1)(6-6x+x^(2))tan(6x-x^(2)-6)dx.Then (J+K) equals

int_(-2)^(2)(dx)/(1+|x-1|)